CompoundList
Molecular formula

C57H104O9

4 compounds have this formula on CompoundList.

Molar mass
933.45g/mol
Monoisotopic mass
932.7680Da
Atoms
170
Elements
3
Rings plus double bonds
6

The formula C57H104O9 describes a molecule made of 57 carbon atoms, 104 hydrogen atoms and 9 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5773.34%
    12.011 × 57 = 684.627 g/mol
  • H Hydrogen × 10411.23%
    1.008 × 104 = 104.832 g/mol
  • O Oxygen × 915.43%
    15.999 × 9 = 143.991 g/mol
Look up another formula

Compounds with the formula C57H104O9

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C57H104O9?

The molar mass of C57H104O9 is 933.45 g/mol, calculated from standard atomic weights for 57 carbon atoms, 104 hydrogen atoms and 9 oxygen atoms. The monoisotopic mass is 932.7680 Da.

How many compounds have the formula C57H104O9?

CompoundList lists 4 compounds with the molecular formula C57H104O9, including Glyceryl triricinoleate, Optase, 2,3-Bis(14-oxooctadecanoyloxy)propyl 14-oxooctadecanoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C57H104O9?

C57H104O9 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.