C57H40N6
1 compound has this formula on CompoundList.
- Molar mass
- 808.99g/mol
- Monoisotopic mass
- 808.3314Da
- Atoms
- 103
- Elements
- 3
- Rings plus double bonds
- 41
The formula C57H40N6 describes a molecule made of 57 carbon atoms, 40 hydrogen atoms and 6 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5784.63%12.011 × 57 = 684.627 g/mol
- H Hydrogen × 404.98%1.008 × 40 = 40.320 g/mol
- N Nitrogen × 610.39%14.007 × 6 = 84.042 g/mol
Compounds with the formula C57H40N6
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C57H40N6?
The molar mass of C57H40N6 is 808.99 g/mol, calculated from standard atomic weights for 57 carbon atoms, 40 hydrogen atoms and 6 nitrogen atoms. The monoisotopic mass is 808.3314 Da.
How many compounds have the formula C57H40N6?
CompoundList lists 1 compound with the molecular formula C57H40N6, including 9-(4-(4,6-Diphenyl-1,3,5-triazin-2-yl) phenyl)-N3, N3, N6, N6-tetraphenyl-9H-carbazole-3,6-diamine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C57H40N6?
C57H40N6 has a degree of unsaturation of 41. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.