CompoundList
Molecular formula

C57H89N7O15

1 compound has this formula on CompoundList.

Molar mass
1112.37g/mol
Monoisotopic mass
1111.6417Da
Atoms
168
Elements
4
Rings plus double bonds
17

The formula C57H89N7O15 describes a molecule made of 57 carbon atoms, 89 hydrogen atoms, 7 nitrogen atoms and 15 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5761.55%
    12.011 × 57 = 684.627 g/mol
  • H Hydrogen × 898.06%
    1.008 × 89 = 89.712 g/mol
  • N Nitrogen × 78.81%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 1521.57%
    15.999 × 15 = 239.985 g/mol
Look up another formula

Compounds with the formula C57H89N7O15

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C57H89N7O15?

The molar mass of C57H89N7O15 is 1112.37 g/mol, calculated from standard atomic weights for 57 carbon atoms, 89 hydrogen atoms, 7 nitrogen atoms and 15 oxygen atoms. The monoisotopic mass is 1111.6417 Da.

How many compounds have the formula C57H89N7O15?

CompoundList lists 1 compound with the molecular formula C57H89N7O15, including Didemnin B. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C57H89N7O15?

C57H89N7O15 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.