CompoundList
Molecular formula

C58H104O6

2 compounds have this formula on CompoundList.

Molar mass
897.46g/mol
Monoisotopic mass
901.8147Da
Atoms
168
Elements
3
Rings plus double bonds
7

The formula C58H104O6 describes a molecule made of 58 carbon atoms, 104 hydrogen atoms and 6 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5877.62%
    12.011 × 58 = 696.638 g/mol
  • H Hydrogen × 10411.68%
    1.008 × 104 = 104.832 g/mol
  • O Oxygen × 610.70%
    15.999 × 6 = 95.994 g/mol
Look up another formula

Compounds with the formula C58H104O6

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C58H104O6?

The molar mass of C58H104O6 is 897.46 g/mol, calculated from standard atomic weights for 58 carbon atoms, 104 hydrogen atoms and 6 oxygen atoms. The monoisotopic mass is 901.8147 Da.

How many compounds have the formula C58H104O6?

CompoundList lists 2 compounds with the molecular formula C58H104O6, including [1,1,2,3,3-Pentadeuterio-1,3-bis[[(E)-octadec-9-enoyl]oxy]propan-2-yl] (10E,13E)-nonadeca-10,13-dienoate, 2-(((10Z,13Z)-Nonadeca-10,13-dienoyl)oxy)propane-1,3-diyl dioleate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C58H104O6?

C58H104O6 has a degree of unsaturation of 7. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.