C58H118O24
1 compound has this formula on CompoundList.
- Molar mass
- 1199.56g/mol
- Monoisotopic mass
- 1198.8013Da
- Atoms
- 200
- Elements
- 3
- Rings plus double bonds
- 0
The formula C58H118O24 describes a molecule made of 58 carbon atoms, 118 hydrogen atoms and 24 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5858.07%12.011 × 58 = 696.638 g/mol
- H Hydrogen × 1189.92%1.008 × 118 = 118.944 g/mol
- O Oxygen × 2432.01%15.999 × 24 = 383.976 g/mol
Compounds with the formula C58H118O24
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C58H118O24?
The molar mass of C58H118O24 is 1199.56 g/mol, calculated from standard atomic weights for 58 carbon atoms, 118 hydrogen atoms and 24 oxygen atoms. The monoisotopic mass is 1198.8013 Da.
How many compounds have the formula C58H118O24?
CompoundList lists 1 compound with the molecular formula C58H118O24, including Lauromacrogol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C58H118O24?
C58H118O24 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.