C59H101N3O14
3 compounds have this formula on CompoundList.
- Molar mass
- 1076.46g/mol
- Monoisotopic mass
- 1075.7284Da
- Atoms
- 177
- Elements
- 4
- Rings plus double bonds
- 11
The formula C59H101N3O14 describes a molecule made of 59 carbon atoms, 101 hydrogen atoms, 3 nitrogen atoms and 14 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5965.83%12.011 × 59 = 708.649 g/mol
- H Hydrogen × 1019.46%1.008 × 101 = 101.808 g/mol
- N Nitrogen × 33.90%14.007 × 3 = 42.021 g/mol
- O Oxygen × 1420.81%15.999 × 14 = 223.986 g/mol
Compounds with the formula C59H101N3O14
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
![[(3E,5E,15Z,21E)-24-[(E)-9-Acetyloxy-7-[2-(dimethylamino)propanoyloxy]-12-[formyl(methyl)amino]-3-hydroxy-4,8,10-trimethyldodec-11-en-2-yl]-8-hydroxy-14,20-dimethoxy-9,11,15,18-tetramethyl-2-oxo-1-oxacyclotetracosa-3,5,15,21-tetraen-10-yl] 2-(dimethylamino)-3-methoxypropanoate chemical structure, C59H101N3O14, CAS 151923-85-2](/s/LBWIGLNHANBXDK-GCQADJLQSA-N.svg)
Frequently asked questions
What is the molar mass of C59H101N3O14?
The molar mass of C59H101N3O14 is 1076.46 g/mol, calculated from standard atomic weights for 59 carbon atoms, 101 hydrogen atoms, 3 nitrogen atoms and 14 oxygen atoms. The monoisotopic mass is 1075.7284 Da.
How many compounds have the formula C59H101N3O14?
CompoundList lists 3 compounds with the molecular formula C59H101N3O14, including Aplyronine A, [(3E,5E,15Z,21E)-24-[(E)-9-Acetyloxy-7-[2-(dimethylamino)propanoyloxy]-12-[formyl(methyl)amino]-3-hydroxy-4,8,10-trimethyldodec-11-en-2-yl]-8-hydroxy-14,20-dimethoxy-9,11,15,18-tetramethyl-2-oxo-1-oxacyclotetracosa-3,5,15,21-tetraen-10-yl] 2-(dimethylamino)-3-methoxypropanoate, Orb1941787. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C59H101N3O14?
C59H101N3O14 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.