CompoundList
Molecular formula

C5H13O3PS2

3 compounds have this formula on CompoundList.

Molar mass
216.25g/mol
Monoisotopic mass
216.0044Da
Atoms
24
Elements
5
Rings plus double bonds
0

The formula C5H13O3PS2 describes a molecule made of 5 carbon atoms, 13 hydrogen atoms, 3 oxygen atoms, 1 phosphorus atom and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 527.77%
    12.011 × 5 = 60.055 g/mol
  • H Hydrogen × 136.06%
    1.008 × 13 = 13.104 g/mol
  • O Oxygen × 322.20%
    15.999 × 3 = 47.997 g/mol
  • P Phosphorus × 114.32%
    30.974 × 1 = 30.974 g/mol
  • S Sulfur × 229.65%
    32.06 × 2 = 64.120 g/mol
Look up another formula

Compounds with the formula C5H13O3PS2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C5H13O3PS2?

The molar mass of C5H13O3PS2 is 216.25 g/mol, calculated from standard atomic weights for 5 carbon atoms, 13 hydrogen atoms, 3 oxygen atoms, 1 phosphorus atom and 2 sulfur atoms. The monoisotopic mass is 216.0044 Da.

How many compounds have the formula C5H13O3PS2?

CompoundList lists 3 compounds with the molecular formula C5H13O3PS2, including Demephion-S, Demephion-O, Dimethyl [bis(methylsulfanyl)methyl]phosphonate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C5H13O3PS2?

C5H13O3PS2 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.