CompoundList
Molecular formula

C5H4Cl3N3

11 compounds have this formula on CompoundList.

Molar mass
212.46g/mol
Monoisotopic mass
210.9471Da
Atoms
15
Elements
4
Rings plus double bonds
4

The formula C5H4Cl3N3 describes a molecule made of 5 carbon atoms, 4 hydrogen atoms, 3 chlorine atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 528.27%
    12.011 × 5 = 60.055 g/mol
  • H Hydrogen × 41.90%
    1.008 × 4 = 4.032 g/mol
  • Cl Chlorine × 350.06%
    35.45 × 3 = 106.350 g/mol
  • N Nitrogen × 319.78%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C5H4Cl3N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C5H4Cl3N3?

The molar mass of C5H4Cl3N3 is 212.46 g/mol, calculated from standard atomic weights for 5 carbon atoms, 4 hydrogen atoms, 3 chlorine atoms and 3 nitrogen atoms. The monoisotopic mass is 210.9471 Da.

How many compounds have the formula C5H4Cl3N3?

CompoundList lists 11 compounds with the molecular formula C5H4Cl3N3, including 2,3,5-Trichloro-6-hydrazinylpyridine, 3,5,6-Trichloropyridine-2,4-diamine, 4,6-Dichloro-5-(chloromethyl)pyrimidin-2-amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C5H4Cl3N3?

C5H4Cl3N3 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.