C5H5IOS
5 compounds have this formula on CompoundList.
- Molar mass
- 240.05g/mol
- Monoisotopic mass
- 239.9106Da
- Atoms
- 13
- Elements
- 5
- Rings plus double bonds
- 3
The formula C5H5IOS describes a molecule made of 5 carbon atoms, 5 hydrogen atoms, 1 iodine atom, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 525.02%12.011 × 5 = 60.055 g/mol
- H Hydrogen × 52.10%1.008 × 5 = 5.040 g/mol
- I Iodine × 152.86%126.9 × 1 = 126.900 g/mol
- O Oxygen × 16.66%15.999 × 1 = 15.999 g/mol
- S Sulfur × 113.36%32.06 × 1 = 32.060 g/mol
Compounds with the formula C5H5IOS
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 5 of 5 compounds
Frequently asked questions
What is the molar mass of C5H5IOS?
The molar mass of C5H5IOS is 240.05 g/mol, calculated from standard atomic weights for 5 carbon atoms, 5 hydrogen atoms, 1 iodine atom, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 239.9106 Da.
How many compounds have the formula C5H5IOS?
CompoundList lists 5 compounds with the molecular formula C5H5IOS, including 2-Iodo-3-methoxythiophene, (5-Iodothiophen-2-yl)methanol, 2-Iodo-5-methoxythiophene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C5H5IOS?
C5H5IOS has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.