Molecular formula

C₅H₇BF₅KO

1 compound has this formula on CompoundList.

Molar mass: 228.01g/mol
Monoisotopic mass: 228.0147Da
Atoms: 20
Elements: 6

The formula C5H7BF5KO describes a molecule made of 5 carbon atoms, 7 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 526.34%
12.011 × 5 = 60.055 g/mol
H Hydrogen × 73.09%
1.008 × 7 = 7.056 g/mol
B Boron × 14.74%
10.81 × 1 = 10.810 g/mol
F Fluorine × 541.66%
18.998 × 5 = 94.990 g/mol
K Potassium × 117.15%
39.098 × 1 = 39.098 g/mol
O Oxygen × 17.02%
15.999 × 1 = 15.999 g/mol

Look up another formula

Compounds with the formula C5H7BF5KO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

rac-Potassium [(1R,3S)-2,2-difluoro-3-(methoxymethyl)cyclopropyl]trifluoroboranuide

CAS 2416056-38-5C₅H₇BF₅KO

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What is the molar mass of C5H7BF5KO?

The molar mass of C5H7BF5KO is 228.01 g/mol, calculated from standard atomic weights for 5 carbon atoms, 7 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 1 oxygen atom. The monoisotopic mass is 228.0147 Da.

How many compounds have the formula C5H7BF5KO?

CompoundList lists 1 compound with the molecular formula C5H7BF5KO, including rac-Potassium [(1R,3S)-2,2-difluoro-3-(methoxymethyl)cyclopropyl]trifluoroboranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.