CompoundList
Molecular formula

C5H7BLiNO3

1 compound has this formula on CompoundList.

Molar mass
146.87g/mol
Monoisotopic mass
147.0679Da
Atoms
18
Elements
6

The formula C5H7BLiNO3 describes a molecule made of 5 carbon atoms, 7 hydrogen atoms, 1 boron atom, 1 lithium atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 540.89%
    12.011 × 5 = 60.055 g/mol
  • H Hydrogen × 74.80%
    1.008 × 7 = 7.056 g/mol
  • B Boron × 17.36%
    10.81 × 1 = 10.810 g/mol
  • Li Lithium × 14.73%
    6.94 × 1 = 6.940 g/mol
  • N Nitrogen × 19.54%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 332.68%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C5H7BLiNO3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C5H7BLiNO3?

The molar mass of C5H7BLiNO3 is 146.87 g/mol, calculated from standard atomic weights for 5 carbon atoms, 7 hydrogen atoms, 1 boron atom, 1 lithium atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 147.0679 Da.

How many compounds have the formula C5H7BLiNO3?

CompoundList lists 1 compound with the molecular formula C5H7BLiNO3, including Lithium(1+) trihydroxy(pyridin-2-yl)boranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.