C61H107N3O34
1 compound has this formula on CompoundList.
- Molar mass
- 1426.51g/mol
- Monoisotopic mass
- 1425.6736Da
- Atoms
- 205
- Elements
- 4
- Rings plus double bonds
- 10
The formula C61H107N3O34 describes a molecule made of 61 carbon atoms, 107 hydrogen atoms, 3 nitrogen atoms and 34 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6151.36%12.011 × 61 = 732.671 g/mol
- H Hydrogen × 1077.56%1.008 × 107 = 107.856 g/mol
- N Nitrogen × 32.95%14.007 × 3 = 42.021 g/mol
- O Oxygen × 3438.13%15.999 × 34 = 543.966 g/mol
Compounds with the formula C61H107N3O34
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C61H107N3O34?
The molar mass of C61H107N3O34 is 1426.51 g/mol, calculated from standard atomic weights for 61 carbon atoms, 107 hydrogen atoms, 3 nitrogen atoms and 34 oxygen atoms. The monoisotopic mass is 1425.6736 Da.
How many compounds have the formula C61H107N3O34?
CompoundList lists 1 compound with the molecular formula C61H107N3O34, including Orb3144620. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C61H107N3O34?
C61H107N3O34 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.