C61H88O17
1 compound has this formula on CompoundList.
- Molar mass
- 1093.36g/mol
- Monoisotopic mass
- 1092.6022Da
- Atoms
- 166
- Elements
- 3
- Rings plus double bonds
- 18
The formula C61H88O17 describes a molecule made of 61 carbon atoms, 88 hydrogen atoms and 17 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6167.01%12.011 × 61 = 732.671 g/mol
- H Hydrogen × 888.11%1.008 × 88 = 88.704 g/mol
- O Oxygen × 1724.88%15.999 × 17 = 271.983 g/mol
Compounds with the formula C61H88O17
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C61H88O17?
The molar mass of C61H88O17 is 1093.36 g/mol, calculated from standard atomic weights for 61 carbon atoms, 88 hydrogen atoms and 17 oxygen atoms. The monoisotopic mass is 1092.6022 Da.
How many compounds have the formula C61H88O17?
CompoundList lists 1 compound with the molecular formula C61H88O17, including Longestin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C61H88O17?
C61H88O17 has a degree of unsaturation of 18. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.