CompoundList
Molecular formula

C63H88N2O14

1 compound has this formula on CompoundList.

Molar mass
1097.40g/mol
Monoisotopic mass
1096.6236Da
Atoms
167
Elements
4
Rings plus double bonds
21

The formula C63H88N2O14 describes a molecule made of 63 carbon atoms, 88 hydrogen atoms, 2 nitrogen atoms and 14 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 6368.95%
    12.011 × 63 = 756.693 g/mol
  • H Hydrogen × 888.08%
    1.008 × 88 = 88.704 g/mol
  • N Nitrogen × 22.55%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 1420.41%
    15.999 × 14 = 223.986 g/mol
Look up another formula

Compounds with the formula C63H88N2O14

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C63H88N2O14?

The molar mass of C63H88N2O14 is 1097.40 g/mol, calculated from standard atomic weights for 63 carbon atoms, 88 hydrogen atoms, 2 nitrogen atoms and 14 oxygen atoms. The monoisotopic mass is 1096.6236 Da.

How many compounds have the formula C63H88N2O14?

CompoundList lists 1 compound with the molecular formula C63H88N2O14, including Milbemycin, oxime. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C63H88N2O14?

C63H88N2O14 has a degree of unsaturation of 21. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.