C67H79Cl2N3O21
1 compound has this formula on CompoundList.
- Molar mass
- 1333.27g/mol
- Monoisotopic mass
- 1331.4583Da
- Atoms
- 172
- Elements
- 5
- Rings plus double bonds
- 29
The formula C67H79Cl2N3O21 describes a molecule made of 67 carbon atoms, 79 hydrogen atoms, 2 chlorine atoms, 3 nitrogen atoms and 21 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6760.36%12.011 × 67 = 804.737 g/mol
- H Hydrogen × 795.97%1.008 × 79 = 79.632 g/mol
- Cl Chlorine × 25.32%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 33.15%14.007 × 3 = 42.021 g/mol
- O Oxygen × 2125.20%15.999 × 21 = 335.979 g/mol
Compounds with the formula C67H79Cl2N3O21
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C67H79Cl2N3O21?
The molar mass of C67H79Cl2N3O21 is 1333.27 g/mol, calculated from standard atomic weights for 67 carbon atoms, 79 hydrogen atoms, 2 chlorine atoms, 3 nitrogen atoms and 21 oxygen atoms. The monoisotopic mass is 1331.4583 Da.
How many compounds have the formula C67H79Cl2N3O21?
CompoundList lists 1 compound with the molecular formula C67H79Cl2N3O21, including Ipg-4 AM. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C67H79Cl2N3O21?
C67H79Cl2N3O21 has a degree of unsaturation of 29. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.