CompoundList
Molecular formula

C69H107N15O17

1 compound has this formula on CompoundList.

Molar mass
1418.70g/mol
Monoisotopic mass
1417.7969Da
Atoms
208
Elements
4
Rings plus double bonds
24

The formula C69H107N15O17 describes a molecule made of 69 carbon atoms, 107 hydrogen atoms, 15 nitrogen atoms and 17 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 6958.42%
    12.011 × 69 = 828.759 g/mol
  • H Hydrogen × 1077.60%
    1.008 × 107 = 107.856 g/mol
  • N Nitrogen × 1514.81%
    14.007 × 15 = 210.105 g/mol
  • O Oxygen × 1719.17%
    15.999 × 17 = 271.983 g/mol
Look up another formula

Compounds with the formula C69H107N15O17

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C69H107N15O17?

The molar mass of C69H107N15O17 is 1418.70 g/mol, calculated from standard atomic weights for 69 carbon atoms, 107 hydrogen atoms, 15 nitrogen atoms and 17 oxygen atoms. The monoisotopic mass is 1417.7969 Da.

How many compounds have the formula C69H107N15O17?

CompoundList lists 1 compound with the molecular formula C69H107N15O17, including Cerexin B. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C69H107N15O17?

C69H107N15O17 has a degree of unsaturation of 24. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.