C69H51N5
1 compound has this formula on CompoundList.
- Molar mass
- 950.20g/mol
- Monoisotopic mass
- 949.4144Da
- Atoms
- 125
- Elements
- 3
- Rings plus double bonds
- 47
The formula C69H51N5 describes a molecule made of 69 carbon atoms, 51 hydrogen atoms and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6987.22%12.011 × 69 = 828.759 g/mol
- H Hydrogen × 515.41%1.008 × 51 = 51.408 g/mol
- N Nitrogen × 57.37%14.007 × 5 = 70.035 g/mol
Compounds with the formula C69H51N5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C69H51N5?
The molar mass of C69H51N5 is 950.20 g/mol, calculated from standard atomic weights for 69 carbon atoms, 51 hydrogen atoms and 5 nitrogen atoms. The monoisotopic mass is 949.4144 Da.
How many compounds have the formula C69H51N5?
CompoundList lists 1 compound with the molecular formula C69H51N5, including Terpene resin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C69H51N5?
C69H51N5 has a degree of unsaturation of 47. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.