C6H11ClFNO4
2 compounds have this formula on CompoundList.
- Molar mass
- 215.61g/mol
- Monoisotopic mass
- 215.0361Da
- Atoms
- 24
- Elements
- 6
- Rings plus double bonds
- 1
The formula C6H11ClFNO4 describes a molecule made of 6 carbon atoms, 11 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 633.43%12.011 × 6 = 72.066 g/mol
- H Hydrogen × 115.14%1.008 × 11 = 11.088 g/mol
- Cl Chlorine × 116.44%35.45 × 1 = 35.450 g/mol
- F Fluorine × 18.81%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 16.50%14.007 × 1 = 14.007 g/mol
- O Oxygen × 429.68%15.999 × 4 = 63.996 g/mol
Compounds with the formula C6H11ClFNO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C6H11ClFNO4?
The molar mass of C6H11ClFNO4 is 215.61 g/mol, calculated from standard atomic weights for 6 carbon atoms, 11 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 215.0361 Da.
How many compounds have the formula C6H11ClFNO4?
CompoundList lists 2 compounds with the molecular formula C6H11ClFNO4, including (2S,4S)-2-Amino-4-fluoro-5-methoxy-5-oxopentanoic acid hydrochloride, (2S,4R)-2-Amino-4-fluoro-5-methoxy-5-oxopentanoic acid hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C6H11ClFNO4?
C6H11ClFNO4 has a degree of unsaturation of 1. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.