C71H103N23O25S4
2 compounds have this formula on CompoundList.
- Molar mass
- 1806.98g/mol
- Monoisotopic mass
- 1805.6378Da
- Atoms
- 226
- Elements
- 5
- Rings plus double bonds
- 32
The formula C71H103N23O25S4 describes a molecule made of 71 carbon atoms, 103 hydrogen atoms, 23 nitrogen atoms, 25 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 7147.19%12.011 × 71 = 852.781 g/mol
- H Hydrogen × 1035.75%1.008 × 103 = 103.824 g/mol
- N Nitrogen × 2317.83%14.007 × 23 = 322.161 g/mol
- O Oxygen × 2522.13%15.999 × 25 = 399.975 g/mol
- S Sulfur × 47.10%32.06 × 4 = 128.240 g/mol
Compounds with the formula C71H103N23O25S4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C71H103N23O25S4?
The molar mass of C71H103N23O25S4 is 1806.98 g/mol, calculated from standard atomic weights for 71 carbon atoms, 103 hydrogen atoms, 23 nitrogen atoms, 25 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 1805.6378 Da.
How many compounds have the formula C71H103N23O25S4?
CompoundList lists 2 compounds with the molecular formula C71H103N23O25S4, including alpha-Conotoxin VC 1.1, Mgmrmmftvf llvvlattvv sstsgrrefr grnaaakasd lvsltdkkrg ccsdprcnyd hpeicg. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C71H103N23O25S4?
C71H103N23O25S4 has a degree of unsaturation of 32. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.