C72H14O2
3 compounds have this formula on CompoundList.
- Molar mass
- 910.90g/mol
- Monoisotopic mass
- 915.1308Da
- Atoms
- 88
- Elements
- 3
- Rings plus double bonds
- 66
The formula C72H14O2 describes a molecule made of 72 carbon atoms, 14 hydrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 7294.94%12.011 × 72 = 864.792 g/mol
- H Hydrogen × 141.55%1.008 × 14 = 14.112 g/mol
- O Oxygen × 23.51%15.999 × 2 = 31.998 g/mol
Compounds with the formula C72H14O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
![3'H-Cyclopropa[1,9] [5,6]fullerene-C60-Ih-3'-butanoic acid 3'-phenyl methyl ester chemical structure, C72H14O2, CAS 160848-21-5](/s/MCEWYIDBDVPMES-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C72H14O2?
The molar mass of C72H14O2 is 910.90 g/mol, calculated from standard atomic weights for 72 carbon atoms, 14 hydrogen atoms and 2 oxygen atoms. The monoisotopic mass is 915.1308 Da.
How many compounds have the formula C72H14O2?
CompoundList lists 3 compounds with the molecular formula C72H14O2, including 3'H-Cyclopropa[1,9] [5,6]fullerene-C60-Ih-3'-butanoic acid 3'-phenyl methyl ester, (6,6)-Pentadeuterophenyl C61 butyric acid methyl ester, 3'H-Cyclopropa(1,9)(5,6)fullerene-C60-Ih-3'-butanoic acid, 3'-phenyl-, methyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C72H14O2?
C72H14O2 has a degree of unsaturation of 66. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.