C78H140N11O34P
1 compound has this formula on CompoundList.
- Molar mass
- 1807.00g/mol
- Monoisotopic mass
- 1805.9302Da
- Atoms
- 264
- Elements
- 5
- Rings plus double bonds
- 15
The formula C78H140N11O34P describes a molecule made of 78 carbon atoms, 140 hydrogen atoms, 11 nitrogen atoms, 34 oxygen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 7851.85%12.011 × 78 = 936.858 g/mol
- H Hydrogen × 1407.81%1.008 × 140 = 141.120 g/mol
- N Nitrogen × 118.53%14.007 × 11 = 154.077 g/mol
- O Oxygen × 3430.10%15.999 × 34 = 543.966 g/mol
- P Phosphorus × 11.71%30.974 × 1 = 30.974 g/mol
Compounds with the formula C78H140N11O34P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C78H140N11O34P?
The molar mass of C78H140N11O34P is 1807.00 g/mol, calculated from standard atomic weights for 78 carbon atoms, 140 hydrogen atoms, 11 nitrogen atoms, 34 oxygen atoms and 1 phosphorus atom. The monoisotopic mass is 1805.9302 Da.
How many compounds have the formula C78H140N11O34P?
CompoundList lists 1 compound with the molecular formula C78H140N11O34P, including Cemdisiran, terminal sugar modification-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C78H140N11O34P?
C78H140N11O34P has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.