C7H15BF4N2
2 compounds have this formula on CompoundList.
- Molar mass
- 214.01g/mol
- Monoisotopic mass
- 214.1264Da
- Atoms
- 29
- Elements
- 5
The formula C7H15BF4N2 describes a molecule made of 7 carbon atoms, 15 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 2 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 739.29%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 157.06%1.008 × 15 = 15.120 g/mol
- B Boron × 15.05%10.81 × 1 = 10.810 g/mol
- F Fluorine × 435.51%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 213.09%14.007 × 2 = 28.014 g/mol
Compounds with the formula C7H15BF4N2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
![1-Methyl-1,4-diazabicyclo[2.2.2]octan-1-ium tetrafluoroborate chemical structure, C7H15BF4N2, CAS 141922-56-7](/s/COOSWYMTPBWXBE-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C7H15BF4N2?
The molar mass of C7H15BF4N2 is 214.01 g/mol, calculated from standard atomic weights for 7 carbon atoms, 15 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 2 nitrogen atoms. The monoisotopic mass is 214.1264 Da.
How many compounds have the formula C7H15BF4N2?
CompoundList lists 2 compounds with the molecular formula C7H15BF4N2, including RefChem:580136, 1-Methyl-1,4-diazabicyclo[2.2.2]octan-1-ium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.