C7H18BF4N
2 compounds have this formula on CompoundList.
- Molar mass
- 203.03g/mol
- Monoisotopic mass
- 203.1468Da
- Atoms
- 31
- Elements
- 5
The formula C7H18BF4N describes a molecule made of 7 carbon atoms, 18 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 741.41%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 188.94%1.008 × 18 = 18.144 g/mol
- B Boron × 15.32%10.81 × 1 = 10.810 g/mol
- F Fluorine × 437.43%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 16.90%14.007 × 1 = 14.007 g/mol
Compounds with the formula C7H18BF4N
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C7H18BF4N?
The molar mass of C7H18BF4N is 203.03 g/mol, calculated from standard atomic weights for 7 carbon atoms, 18 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. The monoisotopic mass is 203.1468 Da.
How many compounds have the formula C7H18BF4N?
CompoundList lists 2 compounds with the molecular formula C7H18BF4N, including Triethylmethylammonium tetrafluoroborate, Butyl(trimethyl)azanium, tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.