CompoundList
Molecular formula

C7H2BrF5

21 compounds have this formula on CompoundList.

Molar mass
260.99g/mol
Monoisotopic mass
259.9260Da
Atoms
15
Elements
4
Rings plus double bonds
4

The formula C7H2BrF5 describes a molecule made of 7 carbon atoms, 2 hydrogen atoms, 1 bromine atom and 5 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 732.22%
    12.011 × 7 = 84.077 g/mol
  • H Hydrogen × 20.77%
    1.008 × 2 = 2.016 g/mol
  • Br Bromine × 130.62%
    79.904 × 1 = 79.904 g/mol
  • F Fluorine × 536.40%
    18.998 × 5 = 94.990 g/mol
Look up another formula

Compounds with the formula C7H2BrF5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 21 of 21 compounds

Frequently asked questions

What is the molar mass of C7H2BrF5?

The molar mass of C7H2BrF5 is 260.99 g/mol, calculated from standard atomic weights for 7 carbon atoms, 2 hydrogen atoms, 1 bromine atom and 5 fluorine atoms. The monoisotopic mass is 259.9260 Da.

How many compounds have the formula C7H2BrF5?

CompoundList lists 21 compounds with the molecular formula C7H2BrF5, including Pentafluorobenzyl bromide, 4-Bromo-2,6-difluorobenzotrifluoride, 4-Bromo-3,5-difluorobenzotrifluoride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C7H2BrF5?

C7H2BrF5 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.