C7H3BrF3IO
17 compounds have this formula on CompoundList.
- Molar mass
- 366.90g/mol
- Monoisotopic mass
- 365.8364Da
- Atoms
- 16
- Elements
- 6
- Rings plus double bonds
- 4
The formula C7H3BrF3IO describes a molecule made of 7 carbon atoms, 3 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 1 iodine atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 722.92%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 30.82%1.008 × 3 = 3.024 g/mol
- Br Bromine × 121.78%79.904 × 1 = 79.904 g/mol
- F Fluorine × 315.53%18.998 × 3 = 56.994 g/mol
- I Iodine × 134.59%126.9 × 1 = 126.900 g/mol
- O Oxygen × 14.36%15.999 × 1 = 15.999 g/mol
Compounds with the formula C7H3BrF3IO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 17 of 17 compounds
Frequently asked questions
What is the molar mass of C7H3BrF3IO?
The molar mass of C7H3BrF3IO is 366.90 g/mol, calculated from standard atomic weights for 7 carbon atoms, 3 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 1 iodine atom and 1 oxygen atom. The monoisotopic mass is 365.8364 Da.
How many compounds have the formula C7H3BrF3IO?
CompoundList lists 17 compounds with the molecular formula C7H3BrF3IO, including 4-Bromo-2-(trifluoromethoxy)iodobenzene, 2-Bromo-1-iodo-4-(trifluoromethoxy)benzene, 1-Bromo-3-iodo-5-(trifluoromethoxy)benzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C7H3BrF3IO?
C7H3BrF3IO has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.