CompoundList
Molecular formula

C7H5BrF3NOS

12 compounds have this formula on CompoundList.

Molar mass
288.08g/mol
Monoisotopic mass
286.9227Da
Atoms
19
Elements
7
Rings plus double bonds
4

The formula C7H5BrF3NOS describes a molecule made of 7 carbon atoms, 5 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 1 nitrogen atom, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 729.19%
    12.011 × 7 = 84.077 g/mol
  • H Hydrogen × 51.75%
    1.008 × 5 = 5.040 g/mol
  • Br Bromine × 127.74%
    79.904 × 1 = 79.904 g/mol
  • F Fluorine × 319.78%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 14.86%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 15.55%
    15.999 × 1 = 15.999 g/mol
  • S Sulfur × 111.13%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C7H5BrF3NOS

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C7H5BrF3NOS?

The molar mass of C7H5BrF3NOS is 288.08 g/mol, calculated from standard atomic weights for 7 carbon atoms, 5 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 1 nitrogen atom, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 286.9227 Da.

How many compounds have the formula C7H5BrF3NOS?

CompoundList lists 12 compounds with the molecular formula C7H5BrF3NOS, including (4-Bromophenyl)(imino)(trifluoromethyl)-lambda6-sulfanone, (3-Bromophenyl)(imino)(trifluoromethyl)-lambda6-sulfanone, 2-Amino-6-bromo-4-[(trifluoromethyl)thio]phenol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C7H5BrF3NOS?

C7H5BrF3NOS has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.