C7H6BF4KO
6 compounds have this formula on CompoundList.
- Molar mass
- 232.02g/mol
- Monoisotopic mass
- 232.0085Da
- Atoms
- 20
- Elements
- 6
The formula C7H6BF4KO describes a molecule made of 7 carbon atoms, 6 hydrogen atoms, 1 boron atom, 4 fluorine atoms, 1 potassium atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 736.24%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 62.61%1.008 × 6 = 6.048 g/mol
- B Boron × 14.66%10.81 × 1 = 10.810 g/mol
- F Fluorine × 432.75%18.998 × 4 = 75.992 g/mol
- K Potassium × 116.85%39.098 × 1 = 39.098 g/mol
- O Oxygen × 16.90%15.999 × 1 = 15.999 g/mol
Compounds with the formula C7H6BF4KO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 6 of 6 compounds
Frequently asked questions
What is the molar mass of C7H6BF4KO?
The molar mass of C7H6BF4KO is 232.02 g/mol, calculated from standard atomic weights for 7 carbon atoms, 6 hydrogen atoms, 1 boron atom, 4 fluorine atoms, 1 potassium atom and 1 oxygen atom. The monoisotopic mass is 232.0085 Da.
How many compounds have the formula C7H6BF4KO?
CompoundList lists 6 compounds with the molecular formula C7H6BF4KO, including Potassium (3-fluoro-4-methoxyphenyl)trifluoroborate, Potassium trifluoro(2-fluoro-6-methoxyphenyl)borate, Potassium trifluoro(2-fluoro-5-methoxyphenyl)boranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.