C82H154N34O24
1 compound has this formula on CompoundList.
- Molar mass
- 2000.35g/mol
- Monoisotopic mass
- 1999.1875Da
- Atoms
- 294
- Elements
- 4
- Rings plus double bonds
- 23
The formula C82H154N34O24 describes a molecule made of 82 carbon atoms, 154 hydrogen atoms, 34 nitrogen atoms and 24 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 8249.24%12.011 × 82 = 984.902 g/mol
- H Hydrogen × 1547.76%1.008 × 154 = 155.232 g/mol
- N Nitrogen × 3423.81%14.007 × 34 = 476.238 g/mol
- O Oxygen × 2419.20%15.999 × 24 = 383.976 g/mol
Compounds with the formula C82H154N34O24
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C82H154N34O24?
The molar mass of C82H154N34O24 is 2000.35 g/mol, calculated from standard atomic weights for 82 carbon atoms, 154 hydrogen atoms, 34 nitrogen atoms and 24 oxygen atoms. The monoisotopic mass is 1999.1875 Da.
How many compounds have the formula C82H154N34O24?
CompoundList lists 1 compound with the molecular formula C82H154N34O24, including Parasin I. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C82H154N34O24?
C82H154N34O24 has a degree of unsaturation of 23. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.