CompoundList
Molecular formula

C89H134N24O27

1 compound has this formula on CompoundList.

Molar mass
1972.19g/mol
Monoisotopic mass
1970.9850Da
Atoms
274
Elements
4
Rings plus double bonds
35

The formula C89H134N24O27 describes a molecule made of 89 carbon atoms, 134 hydrogen atoms, 24 nitrogen atoms and 27 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 8954.20%
    12.011 × 89 = 1068.979 g/mol
  • H Hydrogen × 1346.85%
    1.008 × 134 = 135.072 g/mol
  • N Nitrogen × 2417.05%
    14.007 × 24 = 336.168 g/mol
  • O Oxygen × 2721.90%
    15.999 × 27 = 431.973 g/mol
Look up another formula

Compounds with the formula C89H134N24O27

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C89H134N24O27?

The molar mass of C89H134N24O27 is 1972.19 g/mol, calculated from standard atomic weights for 89 carbon atoms, 134 hydrogen atoms, 24 nitrogen atoms and 27 oxygen atoms. The monoisotopic mass is 1970.9850 Da.

How many compounds have the formula C89H134N24O27?

CompoundList lists 1 compound with the molecular formula C89H134N24O27, including C89H134N24O27. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C89H134N24O27?

C89H134N24O27 has a degree of unsaturation of 35. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.