C8H24B2N4
1 compound has this formula on CompoundList.
- Molar mass
- 197.93g/mol
- Monoisotopic mass
- 198.2187Da
- Atoms
- 38
- Elements
- 4
The formula C8H24B2N4 describes a molecule made of 8 carbon atoms, 24 hydrogen atoms, 2 boron atoms and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 848.55%12.011 × 8 = 96.088 g/mol
- H Hydrogen × 2412.22%1.008 × 24 = 24.192 g/mol
- B Boron × 210.92%10.81 × 2 = 21.620 g/mol
- N Nitrogen × 428.31%14.007 × 4 = 56.028 g/mol
Compounds with the formula C8H24B2N4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C8H24B2N4?
The molar mass of C8H24B2N4 is 197.93 g/mol, calculated from standard atomic weights for 8 carbon atoms, 24 hydrogen atoms, 2 boron atoms and 4 nitrogen atoms. The monoisotopic mass is 198.2187 Da.
How many compounds have the formula C8H24B2N4?
CompoundList lists 1 compound with the molecular formula C8H24B2N4, including Diborane(4)tetramine, octamethyl-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.