C8H4ClF5
18 compounds have this formula on CompoundList.
- Molar mass
- 230.56g/mol
- Monoisotopic mass
- 229.9922Da
- Atoms
- 18
- Elements
- 4
- Rings plus double bonds
- 4
The formula C8H4ClF5 describes a molecule made of 8 carbon atoms, 4 hydrogen atoms, 1 chlorine atom and 5 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 841.68%12.011 × 8 = 96.088 g/mol
- H Hydrogen × 41.75%1.008 × 4 = 4.032 g/mol
- Cl Chlorine × 115.38%35.45 × 1 = 35.450 g/mol
- F Fluorine × 541.20%18.998 × 5 = 94.990 g/mol
Compounds with the formula C8H4ClF5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 18 of 18 compounds
Frequently asked questions
What is the molar mass of C8H4ClF5?
The molar mass of C8H4ClF5 is 230.56 g/mol, calculated from standard atomic weights for 8 carbon atoms, 4 hydrogen atoms, 1 chlorine atom and 5 fluorine atoms. The monoisotopic mass is 229.9922 Da.
How many compounds have the formula C8H4ClF5?
CompoundList lists 18 compounds with the molecular formula C8H4ClF5, including 1-(Chlorodifluoromethyl)-4-(trifluoromethyl)benzene, 1-Chloro-2-(pentafluoroethyl)benzene, 1-Chloro-3-(pentafluoroethyl)benzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C8H4ClF5?
C8H4ClF5 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.