C93H109Cl2N11O32
1 compound has this formula on CompoundList.
- Molar mass
- 1963.84g/mol
- Monoisotopic mass
- 1961.6617Da
- Atoms
- 247
- Elements
- 5
- Rings plus double bonds
- 44
The formula C93H109Cl2N11O32 describes a molecule made of 93 carbon atoms, 109 hydrogen atoms, 2 chlorine atoms, 11 nitrogen atoms and 32 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 9356.88%12.011 × 93 = 1117.023 g/mol
- H Hydrogen × 1095.59%1.008 × 109 = 109.872 g/mol
- Cl Chlorine × 23.61%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 117.85%14.007 × 11 = 154.077 g/mol
- O Oxygen × 3226.07%15.999 × 32 = 511.968 g/mol
Compounds with the formula C93H109Cl2N11O32
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C93H109Cl2N11O32?
The molar mass of C93H109Cl2N11O32 is 1963.84 g/mol, calculated from standard atomic weights for 93 carbon atoms, 109 hydrogen atoms, 2 chlorine atoms, 11 nitrogen atoms and 32 oxygen atoms. The monoisotopic mass is 1961.6617 Da.
How many compounds have the formula C93H109Cl2N11O32?
CompoundList lists 1 compound with the molecular formula C93H109Cl2N11O32, including Mideplanin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C93H109Cl2N11O32?
C93H109Cl2N11O32 has a degree of unsaturation of 44. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.