C95H151N5O30
1 compound has this formula on CompoundList.
- Molar mass
- 1843.26g/mol
- Monoisotopic mass
- 1842.0444Da
- Atoms
- 281
- Elements
- 4
- Rings plus double bonds
- 23
The formula C95H151N5O30 describes a molecule made of 95 carbon atoms, 151 hydrogen atoms, 5 nitrogen atoms and 30 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 9561.90%12.011 × 95 = 1141.045 g/mol
- H Hydrogen × 1518.26%1.008 × 151 = 152.208 g/mol
- N Nitrogen × 53.80%14.007 × 5 = 70.035 g/mol
- O Oxygen × 3026.04%15.999 × 30 = 479.970 g/mol
Compounds with the formula C95H151N5O30
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C95H151N5O30?
The molar mass of C95H151N5O30 is 1843.26 g/mol, calculated from standard atomic weights for 95 carbon atoms, 151 hydrogen atoms, 5 nitrogen atoms and 30 oxygen atoms. The monoisotopic mass is 1842.0444 Da.
How many compounds have the formula C95H151N5O30?
CompoundList lists 1 compound with the molecular formula C95H151N5O30, including Monascus red. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C95H151N5O30?
C95H151N5O30 has a degree of unsaturation of 23. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.