CompoundList
Molecular formula

C9F10

5 compounds have this formula on CompoundList.

Molar mass
298.08g/mol
Monoisotopic mass
297.9840Da
Atoms
19
Elements
2
Rings plus double bonds
5

The formula C9F10 describes a molecule made of 9 carbon atoms and 10 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 936.27%
    12.011 × 9 = 108.099 g/mol
  • F Fluorine × 1063.73%
    18.998 × 10 = 189.980 g/mol
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Compounds with the formula C9F10

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 5 of 5 compounds

Frequently asked questions

What is the molar mass of C9F10?

The molar mass of C9F10 is 298.08 g/mol, calculated from standard atomic weights for 9 carbon atoms and 10 fluorine atoms. The monoisotopic mass is 297.9840 Da.

How many compounds have the formula C9F10?

CompoundList lists 5 compounds with the molecular formula C9F10, including 3-(Pentafluorophenyl)pentafluoro-1-propene, 1,1,2,2,3,3,4,5,6,7-Decafluoro-2,3-dihydro-1H-indene, Indene, decafluoro-3a,7a-dihydro-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C9F10?

C9F10 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.