C9H10BClO5
1 compound has this formula on CompoundList.
- Molar mass
- 244.43g/mol
- Monoisotopic mass
- 244.0310Da
- Atoms
- 26
- Elements
- 5
The formula C9H10BClO5 describes a molecule made of 9 carbon atoms, 10 hydrogen atoms, 1 boron atom, 1 chlorine atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 944.22%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 104.12%1.008 × 10 = 10.080 g/mol
- B Boron × 14.42%10.81 × 1 = 10.810 g/mol
- Cl Chlorine × 114.50%35.45 × 1 = 35.450 g/mol
- O Oxygen × 532.73%15.999 × 5 = 79.995 g/mol
Compounds with the formula C9H10BClO5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C9H10BClO5?
The molar mass of C9H10BClO5 is 244.43 g/mol, calculated from standard atomic weights for 9 carbon atoms, 10 hydrogen atoms, 1 boron atom, 1 chlorine atom and 5 oxygen atoms. The monoisotopic mass is 244.0310 Da.
How many compounds have the formula C9H10BClO5?
CompoundList lists 1 compound with the molecular formula C9H10BClO5, including 2-Chloro-4-methoxy-5-(methoxycarbonyl)benzeneboronic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.