C9H10FI
11 compounds have this formula on CompoundList.
- Molar mass
- 264.08g/mol
- Monoisotopic mass
- 263.9811Da
- Atoms
- 21
- Elements
- 4
- Rings plus double bonds
- 4
The formula C9H10FI describes a molecule made of 9 carbon atoms, 10 hydrogen atoms, 1 fluorine atom and 1 iodine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 940.93%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 103.82%1.008 × 10 = 10.080 g/mol
- F Fluorine × 17.19%18.998 × 1 = 18.998 g/mol
- I Iodine × 148.05%126.9 × 1 = 126.900 g/mol
Compounds with the formula C9H10FI
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 11 of 11 compounds
Frequently asked questions
What is the molar mass of C9H10FI?
The molar mass of C9H10FI is 264.08 g/mol, calculated from standard atomic weights for 9 carbon atoms, 10 hydrogen atoms, 1 fluorine atom and 1 iodine atom. The monoisotopic mass is 263.9811 Da.
How many compounds have the formula C9H10FI?
CompoundList lists 11 compounds with the molecular formula C9H10FI, including 2-Fluoro-1-iodo-4-(propan-2-yl)benzene, 1-Fluoro-4-(3-iodopropyl)benzene, 1-Fluoro-4-iodo-2-isopropylbenzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C9H10FI?
C9H10FI has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.