C9H14IP
1 compound has this formula on CompoundList.
- Molar mass
- 280.08g/mol
- Monoisotopic mass
- 279.9878Da
- Atoms
- 25
- Elements
- 4
- Rings plus double bonds
- 3
The formula C9H14IP describes a molecule made of 9 carbon atoms, 14 hydrogen atoms, 1 iodine atom and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 938.60%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 145.04%1.008 × 14 = 14.112 g/mol
- I Iodine × 145.31%126.9 × 1 = 126.900 g/mol
- P Phosphorus × 111.06%30.974 × 1 = 30.974 g/mol
Compounds with the formula C9H14IP
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C9H14IP?
The molar mass of C9H14IP is 280.08 g/mol, calculated from standard atomic weights for 9 carbon atoms, 14 hydrogen atoms, 1 iodine atom and 1 phosphorus atom. The monoisotopic mass is 279.9878 Da.
How many compounds have the formula C9H14IP?
CompoundList lists 1 compound with the molecular formula C9H14IP, including Trimethylphenylphosphonium iodide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C9H14IP?
C9H14IP has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.