C9H15B3O3
2 compounds have this formula on CompoundList.
- Molar mass
- 203.65g/mol
- Monoisotopic mass
- 204.1300Da
- Atoms
- 30
- Elements
- 4
The formula C9H15B3O3 describes a molecule made of 9 carbon atoms, 15 hydrogen atoms, 3 boron atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 953.08%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 157.42%1.008 × 15 = 15.120 g/mol
- B Boron × 315.92%10.81 × 3 = 32.430 g/mol
- O Oxygen × 323.57%15.999 × 3 = 47.997 g/mol
Compounds with the formula C9H15B3O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C9H15B3O3?
The molar mass of C9H15B3O3 is 203.65 g/mol, calculated from standard atomic weights for 9 carbon atoms, 15 hydrogen atoms, 3 boron atoms and 3 oxygen atoms. The monoisotopic mass is 204.1300 Da.
How many compounds have the formula C9H15B3O3?
CompoundList lists 2 compounds with the molecular formula C9H15B3O3, including Tricyclopropyl-1,3,5,2,4,6-trioxatriborinane, 2,4,6-Tri-1-propen-1-ylboroxin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.