C9H21Cl3N3Ru
1 compound has this formula on CompoundList.
- Molar mass
- 378.71g/mol
- Monoisotopic mass
- 377.9845Da
- Atoms
- 37
- Elements
- 5
The formula C9H21Cl3N3Ru describes a molecule made of 9 carbon atoms, 21 hydrogen atoms, 3 chlorine atoms, 3 nitrogen atoms and 1 ruthenium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 928.54%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 215.59%1.008 × 21 = 21.168 g/mol
- Cl Chlorine × 328.08%35.45 × 3 = 106.350 g/mol
- N Nitrogen × 311.10%14.007 × 3 = 42.021 g/mol
- Ru Ruthenium × 126.69%101.07 × 1 = 101.070 g/mol
Compounds with the formula C9H21Cl3N3Ru
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C9H21Cl3N3Ru?
The molar mass of C9H21Cl3N3Ru is 378.71 g/mol, calculated from standard atomic weights for 9 carbon atoms, 21 hydrogen atoms, 3 chlorine atoms, 3 nitrogen atoms and 1 ruthenium atom. The monoisotopic mass is 377.9845 Da.
How many compounds have the formula C9H21Cl3N3Ru?
CompoundList lists 1 compound with the molecular formula C9H21Cl3N3Ru, including 1H-1,4,7-Triazonine, octahydro-1,4,7-trimethyl-, ruthenium complex. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.