C9H4F5N3O2
21 compounds have this formula on CompoundList.
- Molar mass
- 281.14g/mol
- Monoisotopic mass
- 281.0224Da
- Atoms
- 23
- Elements
- 5
- Rings plus double bonds
- 7
The formula C9H4F5N3O2 describes a molecule made of 9 carbon atoms, 4 hydrogen atoms, 5 fluorine atoms, 3 nitrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 938.45%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 41.43%1.008 × 4 = 4.032 g/mol
- F Fluorine × 533.79%18.998 × 5 = 94.990 g/mol
- N Nitrogen × 314.95%14.007 × 3 = 42.021 g/mol
- O Oxygen × 211.38%15.999 × 2 = 31.998 g/mol
Compounds with the formula C9H4F5N3O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 21 of 21 compounds
Frequently asked questions
What is the molar mass of C9H4F5N3O2?
The molar mass of C9H4F5N3O2 is 281.14 g/mol, calculated from standard atomic weights for 9 carbon atoms, 4 hydrogen atoms, 5 fluorine atoms, 3 nitrogen atoms and 2 oxygen atoms. The monoisotopic mass is 281.0224 Da.
How many compounds have the formula C9H4F5N3O2?
CompoundList lists 21 compounds with the molecular formula C9H4F5N3O2, including 6-Nitro-2-(pentafluoroethyl)-1H-benzimidazole, 3-Azidopropanoic acid-PFP ester, 2-(Difluoromethyl)-3-nitro-5-(trifluoromethyl)pyridine-6-acetonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C9H4F5N3O2?
C9H4F5N3O2 has a degree of unsaturation of 7. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.