F6N3P3
1 compound has this formula on CompoundList.
- Molar mass
- 248.93g/mol
- Monoisotopic mass
- 248.9209Da
- Atoms
- 12
- Elements
- 3
The formula F6N3P3 describes a molecule made of 6 fluorine atoms, 3 nitrogen atoms and 3 phosphorus atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- F Fluorine × 645.79%18.998 × 6 = 113.988 g/mol
- N Nitrogen × 316.88%14.007 × 3 = 42.021 g/mol
- P Phosphorus × 337.33%30.974 × 3 = 92.922 g/mol
Compounds with the formula F6N3P3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of F6N3P3?
The molar mass of F6N3P3 is 248.93 g/mol, calculated from standard atomic weights for 6 fluorine atoms, 3 nitrogen atoms and 3 phosphorus atoms. The monoisotopic mass is 248.9209 Da.
How many compounds have the formula F6N3P3?
CompoundList lists 1 compound with the molecular formula F6N3P3, including Hexafluorocyclotriphosphazene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.