H2I3ORh
1 compound has this formula on CompoundList.
- Molar mass
- 501.63g/mol
- Monoisotopic mass
- 501.6295Da
- Atoms
- 7
- Elements
- 4
The formula H2I3ORh describes a molecule made of 2 hydrogen atoms, 3 iodine atoms, 1 oxygen atom and 1 rhodium atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- H Hydrogen × 20.40%1.008 × 2 = 2.016 g/mol
- I Iodine × 375.89%126.9 × 3 = 380.700 g/mol
- O Oxygen × 13.19%15.999 × 1 = 15.999 g/mol
- Rh Rhodium × 120.52%102.91 × 1 = 102.910 g/mol
Compounds with the formula H2I3ORh
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of H2I3ORh?
The molar mass of H2I3ORh is 501.63 g/mol, calculated from standard atomic weights for 2 hydrogen atoms, 3 iodine atoms, 1 oxygen atom and 1 rhodium atom. The monoisotopic mass is 501.6295 Da.
How many compounds have the formula H2I3ORh?
CompoundList lists 1 compound with the molecular formula H2I3ORh, including Rhodium(III)iodide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.