BF3H4O2
We do not list any compound with this exact formula yet.
- Molar mass
- 103.83g/mol
- Atoms
- 10
- Elements
- 4
The formula BF3H4O2 describes a molecule made of 1 boron atom, 3 fluorine atoms, 4 hydrogen atoms and 2 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 110.41%10.81 × 1 = 10.810 g/mol
- F Fluorine × 354.89%18.998 × 3 = 56.994 g/mol
- H Hydrogen × 43.88%1.008 × 4 = 4.032 g/mol
- O Oxygen × 230.82%15.999 × 2 = 31.998 g/mol
Compounds with the formula BF3H4O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of BF3H4O2?
The molar mass of BF3H4O2 is 103.83 g/mol, calculated from standard atomic weights for 1 boron atom, 3 fluorine atoms, 4 hydrogen atoms and 2 oxygen atoms.