B2H8Mg
We do not list any compound with this exact formula yet.
- Molar mass
- 53.99g/mol
- Atoms
- 11
- Elements
- 3
The formula B2H8Mg describes a molecule made of 2 boron atoms, 8 hydrogen atoms and 1 magnesium atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 240.05%10.81 × 2 = 21.620 g/mol
- H Hydrogen × 814.94%1.008 × 8 = 8.064 g/mol
- Mg Magnesium × 145.02%24.305 × 1 = 24.305 g/mol
Compounds with the formula B2H8Mg
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Our database is still growing. Check the formula, try a related one, or post a buy request with the name or CAS number you need.
Frequently asked questions
What is the molar mass of B2H8Mg?
The molar mass of B2H8Mg is 53.99 g/mol, calculated from standard atomic weights for 2 boron atoms, 8 hydrogen atoms and 1 magnesium atom.