CompoundList
Molecular formula

C13H11FIN3

1 compound has this formula on CompoundList.

Molar mass
355.15g/mol
Monoisotopic mass
354.9982Da
Atoms
29
Elements
5
Rings plus double bonds
9

The formula C13H11FIN3 describes a molecule made of 13 carbon atoms, 11 hydrogen atoms, 1 fluorine atom, 1 iodine atom and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1343.97%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 113.12%
    1.008 × 11 = 11.088 g/mol
  • F Fluorine × 15.35%
    18.998 × 1 = 18.998 g/mol
  • I Iodine × 135.73%
    126.9 × 1 = 126.900 g/mol
  • N Nitrogen × 311.83%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C13H11FIN3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C13H11FIN3?

The molar mass of C13H11FIN3 is 355.15 g/mol, calculated from standard atomic weights for 13 carbon atoms, 11 hydrogen atoms, 1 fluorine atom, 1 iodine atom and 3 nitrogen atoms. The monoisotopic mass is 354.9982 Da.

How many compounds have the formula C13H11FIN3?

CompoundList lists 1 compound with the molecular formula C13H11FIN3, including Agh-192. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H11FIN3?

C13H11FIN3 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.