C154H248N36O45
2 compounds have this formula on CompoundList.
- Molar mass
- 3323.88g/mol
- Monoisotopic mass
- 3321.8224Da
- Atoms
- 483
- Elements
- 4
- Rings plus double bonds
- 49
The formula C154H248N36O45 describes a molecule made of 154 carbon atoms, 248 hydrogen atoms, 36 nitrogen atoms and 45 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 15455.65%12.011 × 154 = 1849.694 g/mol
- H Hydrogen × 2487.52%1.008 × 248 = 249.984 g/mol
- N Nitrogen × 3615.17%14.007 × 36 = 504.252 g/mol
- O Oxygen × 4521.66%15.999 × 45 = 719.955 g/mol
Compounds with the formula C154H248N36O45
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C154H248N36O45?
The molar mass of C154H248N36O45 is 3323.88 g/mol, calculated from standard atomic weights for 154 carbon atoms, 248 hydrogen atoms, 36 nitrogen atoms and 45 oxygen atoms. The monoisotopic mass is 3321.8224 Da.
How many compounds have the formula C154H248N36O45?
CompoundList lists 2 compounds with the molecular formula C154H248N36O45, including Pardaxin, H-Gly-Phe-Phe-Ala-Leu-Ile-Pro-Lys-Ile-xiIle-Ser-Ser-Pro-Leu-Phe-Lys-Thr-Leu-Leu-Ser-Ala-Val-Gly-Ser-Ala-Leu-Ser-Ser-Ser-Gly-Gly-Gln-Glu-OH. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C154H248N36O45?
C154H248N36O45 has a degree of unsaturation of 49. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.