C21H14O15
2 compounds have this formula on CompoundList.
- Molar mass
- 506.33g/mol
- Monoisotopic mass
- 506.0333Da
- Atoms
- 50
- Elements
- 3
- Rings plus double bonds
- 15
The formula C21H14O15 describes a molecule made of 21 carbon atoms, 14 hydrogen atoms and 15 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2149.82%12.011 × 21 = 252.231 g/mol
- H Hydrogen × 142.79%1.008 × 14 = 14.112 g/mol
- O Oxygen × 1547.40%15.999 × 15 = 239.985 g/mol
Compounds with the formula C21H14O15
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
![5-(6-Carboxy-2,3,4-trihydroxyphenoxy)-4,4',5',6,6'-pentahydroxy[1,1'-biphenyl]-2,2'-dicarboxylic acid chemical structure, C21H14O15, CAS 124814-79-5](/s/DFVVBTRVNBCCLA-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C21H14O15?
The molar mass of C21H14O15 is 506.33 g/mol, calculated from standard atomic weights for 21 carbon atoms, 14 hydrogen atoms and 15 oxygen atoms. The monoisotopic mass is 506.0333 Da.
How many compounds have the formula C21H14O15?
CompoundList lists 2 compounds with the molecular formula C21H14O15, including Valoneic acid, 5-(6-Carboxy-2,3,4-trihydroxyphenoxy)-4,4',5',6,6'-pentahydroxy[1,1'-biphenyl]-2,2'-dicarboxylic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C21H14O15?
C21H14O15 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.