CompoundList
Molecular formula

C28H39N5O5

11 compounds have this formula on CompoundList.

Molar mass
525.65g/mol
Monoisotopic mass
525.2951Da
Atoms
77
Elements
4
Rings plus double bonds
12

The formula C28H39N5O5 describes a molecule made of 28 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2863.98%
    12.011 × 28 = 336.308 g/mol
  • H Hydrogen × 397.48%
    1.008 × 39 = 39.312 g/mol
  • N Nitrogen × 513.32%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 515.22%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C28H39N5O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C28H39N5O5?

The molar mass of C28H39N5O5 is 525.65 g/mol, calculated from standard atomic weights for 28 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 525.2951 Da.

How many compounds have the formula C28H39N5O5?

CompoundList lists 11 compounds with the molecular formula C28H39N5O5, including Enkephalin, Ala(2)-N-pentyl-PheNH(4)-, (S)-Benzyl tert-butyl (6-oxo-6-(4-(pyridin-4-yl)piperazin-1-yl)hexane-1,5-diyl)dicarbamate, Bilaid C1. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C28H39N5O5?

C28H39N5O5 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.