CompoundList
Molecular formula

C33H54N2O7

1 compound has this formula on CompoundList.

Molar mass
590.80g/mol
Monoisotopic mass
590.3931Da
Atoms
96
Elements
4
Rings plus double bonds
8

The formula C33H54N2O7 describes a molecule made of 33 carbon atoms, 54 hydrogen atoms, 2 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3367.09%
    12.011 × 33 = 396.363 g/mol
  • H Hydrogen × 549.21%
    1.008 × 54 = 54.432 g/mol
  • N Nitrogen × 24.74%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 718.96%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C33H54N2O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C33H54N2O7?

The molar mass of C33H54N2O7 is 590.80 g/mol, calculated from standard atomic weights for 33 carbon atoms, 54 hydrogen atoms, 2 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 590.3931 Da.

How many compounds have the formula C33H54N2O7?

CompoundList lists 1 compound with the molecular formula C33H54N2O7, including Terminamine B. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C33H54N2O7?

C33H54N2O7 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.