CompoundList
Molecular formula

C37H55NO10

7 compounds have this formula on CompoundList.

Molar mass
673.84g/mol
Monoisotopic mass
673.3826Da
Atoms
103
Elements
4
Rings plus double bonds
11

The formula C37H55NO10 describes a molecule made of 37 carbon atoms, 55 hydrogen atoms, 1 nitrogen atom and 10 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3765.95%
    12.011 × 37 = 444.407 g/mol
  • H Hydrogen × 558.23%
    1.008 × 55 = 55.440 g/mol
  • N Nitrogen × 12.08%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 1023.74%
    15.999 × 10 = 159.990 g/mol
Look up another formula

Compounds with the formula C37H55NO10

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C37H55NO10?

The molar mass of C37H55NO10 is 673.84 g/mol, calculated from standard atomic weights for 37 carbon atoms, 55 hydrogen atoms, 1 nitrogen atom and 10 oxygen atoms. The monoisotopic mass is 673.3826 Da.

How many compounds have the formula C37H55NO10?

CompoundList lists 7 compounds with the molecular formula C37H55NO10, including RefChem:108338, Stenophylline A, 4,4'-(3,4,7,15,16-Pentahydroxy-4,9-epoxycevane-3,15-diyl)bis(2-methylbut-2-enoic acid). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C37H55NO10?

C37H55NO10 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.